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  • F(x) = ∫ -2^3x sin(t) dt , find F'(x)
    Posted 4 years ago

    If
    F(x) = ∫ -2^3x sin(t) dt ,
    find F'(x)

  • Posted 4 years ago

    the upper limit in the integral above is 3x , hence the integral above has the form

    F(x) = ∫ -2u(x) f(t) dt

    Using the chain rule, we can write

    F '(x) = dF / du * du / dx = 3 sin (3x)

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